This question has Statement-1 and statement-2. Of the four choices given after the Statements, choose the one that best describes the two statements.
If two springs S1 and S2 of force constants k1 and k2, respectively, are stretched by the same force, it is found that more work is done on spring S1 than on spring S2.
Statement-1 : If stretched by the same amount, work done on S1, will be more than that on S2.
Statement -2 : k1 < k2
Stretched by same force hence k1x1 = k2x2
More work is done on spring-1 hence
x1 > x2
k1 < k2
This question involves analyzing two statements about springs and work done. Let's break down the concepts step by step.
Two springs S1 and S2 have force constants k1 and k2. They are stretched by the same force F. It is given that more work is done on S1 than on S2.
The work done W in stretching a spring is given by:
where k is the spring constant and x is the extension.
Also, from Hooke's law, the force F required to stretch a spring by x is:
For the same force F, the extension x in each spring is:
Work done on S1 is:
Similarly, work on S2 is:
Given that W1 > W2, we have:
So, Statement-2 is true: k1 < k2.
Statement-1 claims that if stretched by the same amount, work done on S1 is more than on S2.
For the same extension x, work done is:
So, W ∝ k. Since k1 < k2, we have:
Thus, for the same extension, work done on S1 is less than on S2, not more. Therefore, Statement-1 is false.
Statement-1 is false, and Statement-2 is true. So, the correct option is:
Statement-1 is false, Statement-2 is true.
Related Topics: Work done by a variable force, Hooke's law, spring systems.
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