Electromagnetic Wave Field Relationship

In electromagnetic waves, the electric field (E) and magnetic field (B) are perpendicular to each other and to the direction of propagation. Their amplitudes are related by the speed of light in vacuum (c).

Step 1: Identify Given Values

Amplitude of magnetic field B₀ = $6.0\times {10}^{-7}\text{T}$

Speed of light c = $3\times {10}^8\text{m/s}$

Step 2: Apply the Relationship Formula

The maximum electric field E₀ is related to the maximum magnetic field B₀ by:

$E_0=c\times B_0$

Step 3: Substitute Values

$E_0=(3\times {10}^8)\times (6.0\times {10}^{-7})$

Step 4: Calculate the Result

$E_0=18\times {10}^1=180\text{V/m}$

Final Answer

The maximum value of electric field is $180\text{V/m}$

Related Topics

• Electromagnetic Wave Propagation
• Maxwell's Equations
• Wave-Particle Duality
• Poynting Vector and Energy Transport

Important Formulae

Electric and magnetic field relationship: $\frac{E_0}{B_0}=c$

Speed of light: c=1μ0ε0

Energy density: $u=\frac{1}{2}{\epsilon }_0{E}^2+\frac{1}{2}\frac{B^2}{{\mu }_0}$