Let E and F be two independent events. The probability that exactly one of them occurs is and the probability of none of them occurring is . If P(T) denotes the probability of occurrence of the event T, then
P(E) (1 – P(F)) + (1 – P(E)) P(E)
P(E) + P(F) – 2P (E) P(F) = ……….(1)
(1 – P(E) – P(F)) P(E) P(F)
1 – P(E) – P(F) + P(E) P(F) ………(2)
P(E) + P(E) – P(E) (PF) P(F)
From (1) & (2)
P(E) P(F)
And P(E) + P(F)
So either
We are given two independent events E and F. We know:
We need to find the individual probabilities P(E) and P(F).
Step 1: Define the Probabilities
Let and .
Since the events are independent, the probability of both occurring is .
Step 2: Probability of None Occurring
The probability that an event does NOT occur is 1 minus the probability that it occurs.
Therefore, the probability that neither E nor F occurs is:
We are told this equals .
This gives us our first equation:
Equation 1:
Step 3: Probability of Exactly One Occurring
The event "exactly one occurs" can happen in two mutually exclusive ways:
The total probability is the sum of these two:
We can simplify the left side:
This gives us our second equation:
Equation 2:
Step 4: Solve the System of Equations
Let's expand Equation 1:
This can be rewritten as:
Let's call this Equation 1a:
Now we have two equations:
Equation 1a:
Equation 2:
Subtract Equation 2 from Equation 1a:
Now we know the product of p and q. Substitute back into Equation 1a:
So now we have:
Sum:
Product:
This means p and q are the roots of the quadratic equation: